C+2H2=CH4
...146g...y g
Zn...+2HCl=ZnCl2...+H2
...2*36.5g...2g
Aflam cantitatea de HCl ce intra in reactia cu Zn
daca in 100g...36.5g acid pur
atunci in 400g...x=36.5*400/100=146g; Acesta este acidul care reactioneaza cu Zn
y=2*146/2*36.5=4 g
...4g...z g
C+2H2=CH4
...2*2g...16g
z=4*16/4=16g metan